Reactor consumption rate for uranium
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While scavenging various site I recovered 100's of kg of Uranium.
When I built a reactor of my own, the output was abysmal and it might have consumed 1kg/sec.
Is this the expected behaviour? I am used to SE1 reactors where a few kg of uranium lasts for days, which is why I am asking.
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I have noticed this aswell. I have also found that the large reactor that uses the enriched uranium seems to be alot more efficient even though each enriched uses 100kg of uranium ore. I maxed out the reactor inventory, 64 tonnes, and Im now at 63.79, using my large heavy ship with 10 large ions front and back and only 6 2.5m batteries and a few solar panels. been at least 40-50 hours of playing
I have noticed this aswell. I have also found that the large reactor that uses the enriched uranium seems to be alot more efficient even though each enriched uses 100kg of uranium ore. I maxed out the reactor inventory, 64 tonnes, and Im now at 63.79, using my large heavy ship with 10 large ions front and back and only 6 2.5m batteries and a few solar panels. been at least 40-50 hours of playing
The complete fission of 1 kg of pure uranium-235 (235U) produces approximately 23 GWh of thermal energy. In technical units, this corresponds to approximately 82 terajoules (TJ)
The complete fission of 1 kg of pure plutonium-239 (239Pu) produces approximately 23,7 GWh of thermal energy. In technical units, this corresponds to an energy of approximately 85 terajoules (TJ)
Plutonium-239 is produced from uranium-238 when a uranium nucleus absorbs a neutron. In a conventional reactor, the produced plutonium-239 undergoes fission along with uranium-235. Theoretically, therefore, it should be possible to fission all natural uranium (both isotopes, 235U and 238U). Our current technology is not yet capable of this, but “fast reactors” (reactors with fast neutrons) point the way toward how it might be achieved.
In a typical todays reactor, the ratio of energy produced from fission of 235U and 239Pu varies over time (as the fuel burns), but on average over the entire fuel cycle, approximately 60% to 70% of the total energy comes from the fission of 235U and 30% to 40% from the fission of 239Pu.
At the beginning of the fuel cycle, 100% of the energy comes from the fission of 235U; at the end of the fuel cycle, half to two-thirds of the energy comes from the fission of 239Pu.
But!
The uranium in the game's reactor disappears without a trace. So, strictly speaking, the energy produced should be calculated using Einstein's equation E=mc² ...
And the energy produced should be 90 exajoules (90EJ), that is, 90 quintillion joules (9 × 10¹⁹ J), or 25 terawatt-hours (25TWh)
Something in the game calculations is very poorly calculated.
As usual...
The complete fission of 1 kg of pure uranium-235 (235U) produces approximately 23 GWh of thermal energy. In technical units, this corresponds to approximately 82 terajoules (TJ)
The complete fission of 1 kg of pure plutonium-239 (239Pu) produces approximately 23,7 GWh of thermal energy. In technical units, this corresponds to an energy of approximately 85 terajoules (TJ)
Plutonium-239 is produced from uranium-238 when a uranium nucleus absorbs a neutron. In a conventional reactor, the produced plutonium-239 undergoes fission along with uranium-235. Theoretically, therefore, it should be possible to fission all natural uranium (both isotopes, 235U and 238U). Our current technology is not yet capable of this, but “fast reactors” (reactors with fast neutrons) point the way toward how it might be achieved.
In a typical todays reactor, the ratio of energy produced from fission of 235U and 239Pu varies over time (as the fuel burns), but on average over the entire fuel cycle, approximately 60% to 70% of the total energy comes from the fission of 235U and 30% to 40% from the fission of 239Pu.
At the beginning of the fuel cycle, 100% of the energy comes from the fission of 235U; at the end of the fuel cycle, half to two-thirds of the energy comes from the fission of 239Pu.
But!
The uranium in the game's reactor disappears without a trace. So, strictly speaking, the energy produced should be calculated using Einstein's equation E=mc² ...
And the energy produced should be 90 exajoules (90EJ), that is, 90 quintillion joules (9 × 10¹⁹ J), or 25 terawatt-hours (25TWh)
Something in the game calculations is very poorly calculated.
As usual...
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